A gaseous mixture of three gases A, B and C has a pressure of 10 atms. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm respectively and if C has mol. wt. of 2.0, what is the weight of C in grams present in the mixture?

Question

A gaseous mixture of three gases A, B and C has a pressure of 10 atms. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm respectively and if C has mol. wt. of 2.0, what is the weight of C in grams present in the mixture? (A) 6 (B) 3 (C) 12 (D) 8

Tardigrade Admin · Accepted Answer

Partial pressure of A = 3 atm Partial pressure of B = 1 atm Total pressure = 10 atm Partial pressure of C(PC)=A+ Total pressure - (partial pressure of A + partial pressure of B) =10-(3+1) Pc=10-4=6 textatm Mol. Wt. of C = 2 Partial pressure of C = Mole fraction of C total pressure 6 = Mole fraction of C× 10 Mole fraction of C=(6/10) Mole fraction of text ! ! ! ! text C ! ! ! ! text = ( textMoles textof ! ! ! ! text C ! ! ! ! text / textTotal textmoles) (6/10)=( textMoles textof text ! ! ! ! text C ! ! ! ! text / text10) Moles of C=(10× 6/10)=6 Moles of text ! ! ! ! text C ! ! ! ! text = ( textWt text.of text. text ! ! ! ! text C ! ! ! ! text / textMol text.wt textof text ! ! ! ! text C ! ! ! ! text ) text6 = ( textWt text. textof text ! ! ! ! text C ! ! ! ! text / text2) Wt. of C=6× 2=12

Q. A gaseous mixture of three gases A, B and C has a pressure of 10 atms. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm respectively and if C has mol. wt. of 2.0, what is the weight of C in grams present in the mixture?

6

3

12

8