A gaseous mixture contains (CO)2(.g.) and N2O(.g.) in 2:5 ratio by mass. The ratio of the number of molecules of (CO)2 (.g.) and N2O(.g.) is:

Question

A gaseous mixture contains (CO)2(.g.) and N2O(.g.) in 2:5 ratio by mass. The ratio of the number of molecules of (CO)2 (.g.) and N2O(.g.) is: (A) 5:2 (B) 2:5 (C) 1:2 (D) 5:4

Tardigrade Admin · Accepted Answer

Number of moles of a substance is equal to the ratio of given mass and its molar mass.
Mass of one mole

C O_{2} = 12 + (2 \times 16) = 44

and one mole

N_{2}

0 = (2 \times 14) + 16 = 44

.
Let the ratio constant be '

w

'.
Number of molecules is equal to the product of number of moles of compound and

N_{A}

.

Hence, ratio of number of molecules of

C O_{2}

(g)

and

N_{2} O

g) is

\frac{( 2 w \times N _{A} ) /44}{( 5 w \times N _{A} ) /44} = 2 : 5

.

Q. A gaseous mixture contains $(CO)_{2} (g)$ and $N_{2} O (g)$ in $2 : 5$ ratio by mass. The ratio of the number of molecules of $(CO)_{2} (g)$ and $N_{2} O (g)$ is:

$5 : 2$

$2 : 5$

$1 : 2$

$5 : 4$

Q. A gaseous mixture contains (CO)2​(g) and N2​O(g) in 2:5 ratio by mass. The ratio of the number of molecules of (CO)2​(g) and N2​O(g) is:

5:2

2:5

1:2

5:4

Q. A gaseous mixture contains $(CO)_{2} (g)$ and $N_{2} O (g)$ in $2 : 5$ ratio by mass. The ratio of the number of molecules of $(CO)_{2} (g)$ and $N_{2} O (g)$ is:

$5 : 2$

$2 : 5$

$1 : 2$

$5 : 4$