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  4. A gaseous mixture contains (CO)2(.g.) and N2O(.g.) in 2:5 ratio by mass. The ratio of the number of molecules of (CO)2 (.g.) and N2O(.g.) is:

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Q. A gaseous mixture contains $\left(CO\right)_{2}\left(\right.g\left.\right)$ and $N_{2}O\left(\right.g\left.\right)$ in $2:5$ ratio by mass. The ratio of the number of molecules of $\left(CO\right)_{2 }\left(\right.g\left.\right)$ and $N_{2}O\left(\right.g\left.\right)$ is:

NTA AbhyasNTA Abhyas 2022

Solution:

Number of moles of a substance is equal to the ratio of given mass and its molar mass.
Mass of one mole $CO _2=12+(2 \times 16)=44$ and one mole $N _2$ $0=(2 \times 14)+16=44$.
Let the ratio constant be ' $w$ '.
Number of molecules is equal to the product of number of moles of compound and $N _{ A }$.
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Hence, ratio of number of molecules of $CO _2$
$(g)$ and $N _2 O$ g) is $\frac{\left(2 w \times N_A\right) / 44}{\left(5 w \times N_A\right) / 44}=2: 5$.