A gaseous mixture contains CH4 and C2H6 in equimolecular proportion. The weight of 2.24litres of this mixture at NTP is :-

Question

A gaseous mixture contains CH4 and C2H6 in equimolecular proportion. The weight of 2.24litres of this mixture at NTP is :- (A) 4.6g (B) 1.6g (C) 2.3g (D) 23g

Tardigrade Admin · Accepted Answer

Total moles =(2 . 24/22 . 4)=0.1 mole of CH4=0.05 Mole of C2H6=0.05 Total mass =0.05× 16+0.05× 30=2.3g

Q. A gaseous mixture contains $C H_{4}$ and $C_{2} H_{6}$ in equimolecular proportion. The weight of $2.24 l i t res$ of this mixture at NTP is :-

$4.6 g$

$1.6 g$

$2.3 g$

$23 g$

Total moles $= \frac{2.24}{22.4} = 0.1$
mole of $C H_{4} = 0.05$
Mole of $C_{2} H_{6} = 0.05$
Total mass $= 0.05 \times 16 + 0.05 \times 30 = 2.3 g$

Q. A gaseous mixture contains CH4​ and C2​H6​ in equimolecular proportion. The weight of 2.24litres of this mixture at NTP is :-

4.6g

1.6g

2.3g

23g