A gaseous hydrocarbon on complete combustion gives 3.38 g of CO2 and 0.690 g of H2O and no other product. The empirical formula of the hydrocarbon is

Question

A gaseous hydrocarbon on complete combustion gives 3.38 g of CO2 and 0.690 g of H2O and no other product. The empirical formula of the hydrocarbon is (A) CH (B) CH2 (C) CH3 (D) The data is not complete

Tardigrade Admin · Accepted Answer

44 g CO2 ≡ 1 mol carbon 3.38 g CO2 = 0.0768 mol carbon 18 g H2O ≡ 2 mol of hydrogen atoms 0.690 g H2O ≡ 0.0767 mol hydrogen atom Mole ratio of C: H =1: 1 ∴ Empirical formula of hydrocarbon is CH

Q. A gaseous hydrocarbon on complete combustion gives $3.38 g$ of $C O_{2}$ and $0.690 g$ of $H_{2} O$ and no other product. The empirical formula of the hydrocarbon is

$C H$

$C H_{2}$

$C H_{3}$

The data is not complete

$44 g C O_{2} \equiv 1$ mol carbon
$3.38 g C O_{2} = 0.0768$ mol carbon
$18 g H_{2} O \equiv 2$ mol of hydrogen atoms
$0.690 g H_{2} O \equiv 0.0767$ mol hydrogen atom
Mole ratio of $C : H = 1 : 1$
$∴$ Empirical formula of hydrocarbon is $C H$

Q. A gaseous hydrocarbon on complete combustion gives 3.38g of CO2​ and 0.690g of H2​O and no other product. The empirical formula of the hydrocarbon is

CH

CH2​

CH3​