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Q. A gaseous hydrocarbon on complete combustion gives $3.38 \,g$ of $CO_2$ and $0.690 \,g$ of $H_2O$ and no other product. The empirical formula of the hydrocarbon is

Some Basic Concepts of Chemistry

Solution:

$44\, g \,CO_{2} \equiv 1$ mol carbon
$3.38\, g\, CO_{2} = 0.0768$ mol carbon
$18\,g\,H_{2}O \equiv 2$ mol of hydrogen atoms
$0.690\,g\,H_{2}O \equiv 0.0767$ mol hydrogen atom
Mole ratio of $C : H =1 : 1$
$\therefore $ Empirical formula of hydrocarbon is $CH$