A gas mixture contains O2 and N2 in the ratio of 1 : 4 by weight. The ratio of their number of molecules is

Question

A gas mixture contains O2 and N2 in the ratio of 1 : 4 by weight. The ratio of their number of molecules is (A) 1: 8 (B) 1: 4 (C) 3: 16 (D) 7: 32

Tardigrade Admin · Accepted Answer

As given, the ratio of moles of O 2: N 2=(1/32): (4/28)=(1/32): (1/7) (As we know, mole =( W / M ) ) The ratio of number of molecules =( N A /32): ( N A /7)=(7/32): 1=7: 32

Q. A gas mixture contains $O_{2}$ and $N_{2}$ in the ratio of $1 : 4$ by weight. The ratio of their number of molecules is

1 : 8

1 : 4

3 : 16

7 : 32

As given, the ratio of moles of $O_{2} : N_{2} = \frac{1}{32} : \frac{4}{28} = \frac{1}{32} : \frac{1}{7}$
(As we know, mole $= \frac{W}{M}$ )
The ratio of number of molecules $= \frac{N _{A}}{32} : \frac{N _{A}}{7} = \frac{7}{32} : 1 = 7 : 32$

Q. A gas mixture contains O2​ and N2​ in the ratio of 1:4 by weight. The ratio of their number of molecules is