A gas mixture contains monoatomic and diatomic molecules of 2 moles each. The mixture has a total internal energy of (symbols have usual meanings)

Question

A gas mixture contains monoatomic and diatomic molecules of 2 moles each. The mixture has a total internal energy of (symbols have usual meanings) (A) 3 RT (B) 5 RT (C) 8 RT (D) 9 RT

Tardigrade Admin · Accepted Answer

C v for monoatomic gas is (3 R /2) C v for diatomic gas is (5 R /2) Total internal energy for mixture U =2 ×((3/2)) RT +2((5/2)) RT U =8 RT

Q. A gas mixture contains monoatomic and diatomic molecules of 2 moles each. The mixture has a total internal energy of (symbols have usual meanings)

$3 RT$

$5 RT$

$8 RT$

$9 RT$

$C_{v}$ for monoatomic gas is $\frac{3 R}{2}$
$C_{v}$ for diatomic gas is $\frac{5 R}{2}$
Total internal energy for mixture
$U = 2 \times (\frac{3}{2}) RT + 2 (\frac{5}{2}) RT$
$U = 8 RT$