A gas mixture contain one mole O2 gas and one mole He gas. Find the ratio of specific heat at constant pressure to that at constant volume of the gaseous mixture.

Question

A gas mixture contain one mole O2 gas and one mole He gas. Find the ratio of specific heat at constant pressure to that at constant volume of the gaseous mixture. (A) 2 (B) 1.5 (C) 2.5 (D) 4

Tardigrade Admin · Accepted Answer

For mixture of gases, CV=((3/2)R+(5/2)R/1+1)=2R CP=2R+R=3R ∴ (CP/CV)=(3/2) (R/R)=1.5

Q. A gas mixture contain one mole $O_{2}$ gas and one mole He gas. Find the ratio of specific heat at constant pressure to that at constant volume of the gaseous mixture.

2

1.5

2.5

4

For mixture of gases,
$C_{V} = \frac{\frac{3}{2} R + \frac{5}{2} R}{1 + 1} = 2 R$
$C_{P} = 2 R + R = 3 R$
$∴ \frac{C _{P}}{C _{V}} = \frac{3}{2} \frac{R}{R} = 1.5$

Q. A gas mixture contain one mole O2​ gas and one mole He gas. Find the ratio of specific heat at constant pressure to that at constant volume of the gaseous mixture.

2

1.5

2.5

4

For mixture of gases, CV​=1+123​R+25​R​=2R CP​=2R+R=3R ∴CV​CP​​=23​RR​=1.5

Q. A gas mixture contain one mole $O_{2}$ gas and one mole He gas. Find the ratio of specific heat at constant pressure to that at constant volume of the gaseous mixture.

For mixture of gases,
$C_{V} = \frac{\frac{3}{2} R + \frac{5}{2} R}{1 + 1} = 2 R$
$C_{P} = 2 R + R = 3 R$
$∴ \frac{C _{P}}{C _{V}} = \frac{3}{2} \frac{R}{R} = 1.5$