A gas mixture 3.67 L in volume contain C 2 H 4 and CH 4 in proportion of 2: 1 by moles and is at 25° C and 1 atm. If the Δ H C ( C 2 H 4) and Δ H C ( CH 4) are -1400 and -900 kJ / mol find heat evolved (in kJ ) on burning this mixture.

Question

A gas mixture 3.67 L in volume contain C 2 H 4 and CH 4 in proportion of 2: 1 by moles and is at 25° C and 1 atm. If the Δ H C ( C 2 H 4) and Δ H C ( CH 4) are -1400 and -900 kJ / mol find heat evolved (in kJ ) on burning this mixture. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

There is 2.44 L C 2 H 4 longrightarrow n =(1 × 2.44/0.082 × 298)=0.1 mol there is 1.22 L CH 4 longrightarrow n =(1 × 1.22/0.082 × 298)=0.05 mol ∴ Heat evolved =0.1 × 1400+0.05 × 900=185 kJ.

Q. A gas mixture $3.67 L$ in volume contain $C_{2} H_{4}$ and $C H_{4}$ in proportion of $2 : 1$ by moles and is at $2 5^{\circ} C$ and $1 a t m$ . If the $Δ H_{C} (C_{2} H_{4})$ and $Δ H_{C} (C H_{4})$ are $- 1400$ and $- 900 k J /$ mol find heat evolved (in $k J$ ) on burning this mixture.

There is $2.44 L C_{2} H_{4} ⟶ n$
$= \frac{1 \times 2.44}{0.082 \times 298} = 0.1 m o l$
there is $1.22 L C H_{4} ⟶ n$
$= \frac{1 \times 1.22}{0.082 \times 298} = 0.05 m o l$
$∴$ Heat evolved
$= 0.1 \times 1400 + 0.05 \times 900 = 185 k J$ .

Q. A gas mixture 3.67L in volume contain C2​H4​ and CH4​ in proportion of 2:1 by moles and is at 25∘C and 1atm. If the ΔHC​(C2​H4​) and ΔHC​(CH4​) are −1400 and −900kJ/ mol find heat evolved (in kJ ) on burning this mixture.

There is 2.44LC2​H4​⟶n =0.082×2981×2.44​=0.1mol there is 1.22LCH4​⟶n =0.082×2981×1.22​=0.05mol ∴ Heat evolved =0.1×1400+0.05×900=185kJ.

Q. A gas mixture $3.67 L$ in volume contain $C_{2} H_{4}$ and $C H_{4}$ in proportion of $2 : 1$ by moles and is at $2 5^{\circ} C$ and $1 a t m$ . If the $Δ H_{C} (C_{2} H_{4})$ and $Δ H_{C} (C H_{4})$ are $- 1400$ and $- 900 k J /$ mol find heat evolved (in $k J$ ) on burning this mixture.

There is $2.44 L C_{2} H_{4} ⟶ n$
$= \frac{1 \times 2.44}{0.082 \times 298} = 0.1 m o l$
there is $1.22 L C H_{4} ⟶ n$
$= \frac{1 \times 1.22}{0.082 \times 298} = 0.05 m o l$
$∴$ Heat evolved
$= 0.1 \times 1400 + 0.05 \times 900 = 185 k J$ .