Question

A gas has a vapour density $\mathrm{11.2.}$ The volume occupied by $lg$ of the gas at NTP is :

• A. 1 L
• B. 11.2 L
• C. 22.4 L
• D. 4 L

Answer 1

Answer: (A)

(i) Molecular weight $=2\times$ vapour density
(ii) Molecular weight in gram $=22.4L$ at STP
Given vapour density $=11.2$ Molecular weight $=2\times 11.2=22.4$
$\therefore 22.4g$ of gas occupies $=22.4L$ at STP
$\therefore 1g$ of gas occupies $=\frac{22.4}{22.4}\times 1$
$=1L$ at $STP$