A gas has a vapour density 11.2. The volume occupied by lg of the gas at NTP is :

Question

A gas has a vapour density 11.2. The volume occupied by lg of the gas at NTP is : (A) 1 L (B) 11.2 L (C) 22.4 L (D) 4 L

Tardigrade Admin · Accepted Answer

(i) Molecular weight =2 × vapour density (ii) Molecular weight in gram =22.4 L at STP Given vapour density =11.2 Molecular weight =2 × 11.2=22.4 ∴ 22.4 g of gas occupies =22.4 L at STP ∴ 1 g of gas occupies =(22.4/22.4) × 1 =1 L at STP

Q. A gas has a vapour density $11.2.$ The volume occupied by $l g$ of the gas at NTP is :

1 L

11.2 L

22.4 L

4 L

(i) Molecular weight $= 2 \times$ vapour density
(ii) Molecular weight in gram $= 22.4 L$ at STP
Given vapour density $= 11.2$ Molecular weight $= 2 \times 11.2 = 22.4$
$∴ 22.4 g$ of gas occupies $= 22.4 L$ at STP
$∴ 1 g$ of gas occupies $= \frac{22.4}{22.4} \times 1$
$= 1 L$ at $STP$

Q. A gas has a vapour density 11.2. The volume occupied by lg of the gas at NTP is :

1 L

11.2 L

22.4 L

4 L

(i) Molecular weight =2× vapour density (ii) Molecular weight in gram =22.4L at STP Given vapour density =11.2 Molecular weight =2×11.2=22.4 ∴22.4g of gas occupies =22.4L at STP ∴1g of gas occupies =22.422.4​×1 =1L at STP

Q. A gas has a vapour density $11.2.$ The volume occupied by $l g$ of the gas at NTP is :

(i) Molecular weight $= 2 \times$ vapour density
(ii) Molecular weight in gram $= 22.4 L$ at STP
Given vapour density $= 11.2$ Molecular weight $= 2 \times 11.2 = 22.4$
$∴ 22.4 g$ of gas occupies $= 22.4 L$ at STP
$∴ 1 g$ of gas occupies $= \frac{22.4}{22.4} \times 1$
$= 1 L$ at $STP$