Question

A gas has a vapour density $\mathrm{11.2.}$ The volume occupied by $1g$ of the gas at NTP is:

• A. $1L$
• B. $11.2L$
• C. $22.4L$
• D. $4L$

Answer 1

Answer: (A)

The vapour density of a gas $=11.2$

$\therefore$ Molecular weight $=2\times$ vapour density

$\therefore$ Molecular weight of a gas $=2\times 11.2=22.4g$

$\therefore 22.4g$ of a gas occupies $=22.4L$ volume

$\therefore 1g$ of a gas occupied $=\frac{22.4}{22.4}\times 1=1L$