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Chemistry
A gas has a vapour density 11.2 . The volume occupied by 1 g of the gas at NTP is:
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Q. A gas has a vapour density $11.2 .$ The volume occupied by $1 g$ of the gas at NTP is:
States of Matter
A
$1 \,L$
23%
B
$11.2 \,L$
27%
C
$22.4\, L$
42%
D
$4\, L$
9%
Solution:
The vapour density of a gas $=11.2$
$\therefore $ Molecular weight $=2 \times$ vapour density
$\therefore $ Molecular weight of a gas $=2 \times 11.2=22.4 g$
$\therefore 22.4 g$ of a gas occupies $=22.4 L$ volume
$\therefore 1 g$ of a gas occupied $=\frac{22.4}{22.4} \times 1=1 L$