Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A gas has a vapour density $11.2 .$ The volume occupied by $1 g$ of the gas at NTP is:

States of Matter

Solution:

The vapour density of a gas $=11.2$

$\therefore $ Molecular weight $=2 \times$ vapour density

$\therefore $ Molecular weight of a gas $=2 \times 11.2=22.4 g$

$\therefore 22.4 g$ of a gas occupies $=22.4 L$ volume

$\therefore 1 g$ of a gas occupied $=\frac{22.4}{22.4} \times 1=1 L$