A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm. The pressure gauge of cylinder indicates 12 atm at 27°C. Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

Question

A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm. The pressure gauge of cylinder indicates 12 atm at 27°C. Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is (A) 42.5°C (B) 67.8°C (C) 99.5°C (D) 25.7° C

Tardigrade Admin · Accepted Answer

(P1/T2)=(P2/T2) (12/300)=(14.9/T2) T2=372.5 K =99.5°C

Q. A gas cylinder containing cooking gas can withstand a pressure of $14.9 a t m$ . The pressure gauge of cylinder indicates $12 a t m$ at $2 7^{\circ} C$ . Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

$42. 5^{\circ} C$

$67. 8^{\circ} C$

$99. 5^{\circ} C$

$25. 7^{\circ} C$

$\frac{P _{1}}{T _{2}} = \frac{P _{2}}{T _{2}}$
$\frac{12}{300} = \frac{14.9}{T _{2}}$
$T_{2} = 372.5 K$
$= 99. 5^{\circ} C$

Q. A gas cylinder containing cooking gas can withstand a pressure of 14.9atm. The pressure gauge of cylinder indicates 12atm at 27∘C. Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

42.5∘C

67.8∘C

99.5∘C

25.7∘C