A gas container contain 35 gm nitrogen gas, 64 gm, O 2 gas and 0.112 lit of CH 4 at STP, what is average molecular weight of the gas mixture?

Question

A gas container contain 35 gm nitrogen gas, 64 gm, O 2 gas and 0.112 lit of CH 4 at STP, what is average molecular weight of the gas mixture? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

35 gm nitrogen =(35/28)=1.25 mole 64 gm oxygen =(64/32)=2 mole 0.112 lit CH 4 at STP =(0.112/22.4)=0.005 mole ∴ Sigma nj =1.25+2+0.005=3.255 ∴ M avg =(1.25 × 28+2 × 32+0.005 × 16/3.255) =(35+64+0.08/3.255)=(99.08/3.255)=30.44

Q. A gas container contain 35gm nitrogen gas, 64gm,O2​ gas and 0.112 lit of CH4​ at STP, what is average molecular weight of the gas mixture?

35gm nitrogen =2835​=1.25 mole 64gm oxygen =3264​=2 mole 0.112 lit CH4​ at STP=22.40.112​=0.005 mole ∴Σnj=1.25+2+0.005=3.255 ∴Mavg​=3.2551.25×28+2×32+0.005×16​ =3.25535+64+0.08​=3.25599.08​=30.44

Q. A gas container contain $35 g m$ nitrogen gas, $64 g m, O_{2}$ gas and $0.112$ lit of $C H_{4}$ at $STP$ , what is average molecular weight of the gas mixture?