Q.
A gardener is digging a plot of land. As he gets tired, he works more slowly. After ′t′ minutes he is digging at a rate of t2square metres per minute. How long will it take him to dig an area of 40 square metres ?
Given, a rate of digging a plot, dtdA=t2 ⇒dA=t2dt
On integrating both sides, we get ∫dA=∫t2dt A=1/22t1/2+C ⇒A=4t+C
When t=0,A=0 then C=0 ∵A=4t but A=40 ∴40=4t⇒t=10 ⇒t=100min