Q. A galvanometer of resistance $20 Ω$ is to be shunted so that only 1% of the current passes through it. Shunt connected is

1910 213 Moving Charges and Magnetism Report Error

A

$99/20 Ω$

14%

B

$9/20 Ω$

13%

C

$20/99 Ω$

62%

D

$2/99 Ω$

12%

Solution:

$S = \frac{G}{\frac{i}{i _{g}} - 1}$