A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 × 10-4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

Question

A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 × 10-4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of (A) 2500 Ω as a shunt (B) 2450 Ω as a shunt (C) 2550 Ω in series (D) 2450 Ω in series

Tardigrade Admin · Accepted Answer

Full deflection current, ig=25 × 4 × 10-4 =100 × 10-4 A R=(V/ig)-G=(25/100 × 10-4)-50 =2450 Ω in series.

Q. A galvanometer of $50$ ohm resistance has $25$ divisions. A current of $4 \times 1 0^{- 4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25$ volts, it should be connected with a resistance of

$2500 Ω$ as a shunt

$2450 Ω$ as a shunt

$2550 Ω$ in series

$2450 Ω$ in series

Full deflection current, $i_{g} = 25 \times 4 \times 1 0^{- 4}$
$= 100 \times 1 0^{- 4} A$
$R = \frac{V}{i _{g}} - G = \frac{25}{100 \times 1 0 ^{- 4}} - 50$
$= 2450 Ω$ in series.

Q. A galvanometer of 50 ohm resistance has 25 divisions. A current of 4×10−4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

2500Ω as a shunt

2450Ω as a shunt

2550Ω in series

2450Ω in series