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  4. A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 × 10-4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

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Q. A galvanometer of $50$ ohm resistance has $25$ divisions. A current of $4 \times 10^{-4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25$ volts, it should be connected with a resistance of

Current Electricity

Solution:

Full deflection current, $i_{g}=25 \times 4 \times 10^{-4}$
$=100 \times 10^{-4} A$
$R=\frac{V}{i_{g}}-G=\frac{25}{100 \times 10^{-4}}-50$
$=2450\, \Omega$ in series.