A galvanic cell is set up from a zinc bar weighing 50 g and 1.0 litre, 1.0 M , CuSO 4 solution. How long would the cell run, assuming it delivers a steady current of 1.0 ampere

Question

A galvanic cell is set up from a zinc bar weighing 50 g and 1.0 litre, 1.0 M , CuSO 4 solution. How long would the cell run, assuming it delivers a steady current of 1.0 ampere (A) 48 hrs (B) 41 hrs (C) 21 hrs (D) 1 hr

Tardigrade Admin · Accepted Answer

1 gram equivalent (65 g Zn ) will give 96500 C. 50 g will give charge =(96500/65) × 50 C I t=(96500/65) × 50 t =(96500/65 × 1) × 50=74230.8 sec =(74230.8/3600)=20.62 hrs ≈ 21 hrs

Q. A galvanic cell is set up from a zinc bar weighing $50 g$ and $1.0$ litre, $1.0 M, C u S O_{4}$ solution. How long would the cell run, assuming it delivers a steady current of $1.0$ ampere

$48 h rs$

$41 h rs$

$21 h rs$

$1 h r$

$1$ gram equivalent $(65$ g $Z n$ ) will give $96500 C$ .

$50 g$ will give charge $= \frac{96500}{65} \times 50 C$

$I t = \frac{96500}{65} \times 50$

$t = \frac{96500}{65 \times 1} \times 50 = 74230.8 sec$

$= \frac{74230.8}{3600} = 20.62 h rs \approx 21 h rs$

Q. A galvanic cell is set up from a zinc bar weighing 50g and 1.0 litre, 1.0M,CuSO4​ solution. How long would the cell run, assuming it delivers a steady current of 1.0 ampere

48hrs

41hrs

21hrs

1hr