Q.
A function is continuous \& differentiable on R0 and satisfies the condition xf′(x)+f(x)=1 throughout its domain, with f(1)=2. Then the range of the function is
xf(x)=x+C f(1)=1+C⇒C=1 f(x)=xx+1 f(x)=1+x1;f′(x)=−x21 ⇒ fis always derivable and decreasing in its domain ⇒ monotonic also f is not bounded.
The graph of y=f(x) is as shown y=1 and x=0 are the two asymptotes and range is R−{1}.