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Q. A function is continuous \& differentiable on $R _0$ and satisfies the condition $x f^{\prime}( x )+f( x )=1$ throughout its domain, with $f(1)=2$. Then the range of the function is

Application of Derivatives

Solution:

image
$x f(x)=x+C $
$f (1)=1+ C \Rightarrow C =1 $
$f(x)=\frac{x+1}{x}$
$f ( x )=1+\frac{1}{ x } ; f ^{\prime}( x )=-\frac{1}{ x ^2} $
$\Rightarrow$ fis always derivable and decreasing in its domain $\Rightarrow$ monotonic also $f$ is not bounded.
The graph of $y=f(x)$ is as shown $y=1$ and $x=0$ are the two asymptotes and range is $R -\{1\}$.