A fully charged capacitor has a capacitance C . It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m . If the temperature of the block is raised by Δ T , the potential difference V across the capacitance is

Question

A fully charged capacitor has a capacitance C . It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m . If the temperature of the block is raised by Δ T , the potential difference V across the capacitance is (A) √(2 m C Δ T/s) (B) (m C Δ T/s) (C) (m s Δ T/C) (D) √(2 m s Δ T/C)

Tardigrade Admin · Accepted Answer

E=((1/2))CV2 ...(i) The energy stored in capacitor is lost in form of heat energy H=ms Δ T ...(ii) From Eqs. (i) and (ii), we have ms Δ T=((1/2))CV2 V= √(2 m s Δ T/C)

$\frac{2 m C Δ T}{s}$

$\frac{m C Δ T}{s}$

$\frac{m s Δ T}{C}$

$\frac{2 m s Δ T}{C}$

$E = (\frac{1}{2}) C V^{2}$ ...(i)
The energy stored in capacitor is lost in form of heat energy
$H = m s Δ T$ ...(ii)
From Eqs. (i) and (ii), we have
$m s Δ T = (\frac{1}{2}) C V^{2}$
$V = \frac{2 m s Δ T}{C}$

Q. A fully charged capacitor has a capacitance C . It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m . If the temperature of the block is raised by ΔT , the potential difference V across the capacitance is

s2mCΔT​​

smCΔT​

CmsΔT​

C2msΔT​​

E=(21​)CV2 ...(i) The energy stored in capacitor is lost in form of heat energy H=msΔT ...(ii) From Eqs. (i) and (ii), we have msΔT=(21​)CV2 V=C2msΔT​​

$\frac{2 m C Δ T}{s}$

$\frac{m C Δ T}{s}$

$\frac{m s Δ T}{C}$

$\frac{2 m s Δ T}{C}$

$E = (\frac{1}{2}) C V^{2}$ ...(i)
The energy stored in capacitor is lost in form of heat energy
$H = m s Δ T$ ...(ii)
From Eqs. (i) and (ii), we have
$m s Δ T = (\frac{1}{2}) C V^{2}$
$V = \frac{2 m s Δ T}{C}$