Which of the statement is incorrect if electrolysis of CH 3 COONa (aq.) is made using Pt electrodes?

Question

Which of the statement is incorrect if electrolysis of CH 3 COONa (aq.) is made using Pt electrodes? (A) Ph of solution increases (B) Molar ratio of gases at anode and cathode is 3: 1 (C) CH 3 C OO - in solution decreases (D) The molar ratio of gases at anode and cathode is 2: 1 .

Tardigrade Admin · Accepted Answer

At anode: 2 CH 3 COO - longrightarrow C 2 H 6+2 CO 2( g )+2 e- At cathode: 2 H ++2 e- longrightarrow H 2(g) ∴ CO 2: H 2=2: 1

Q. Which of the statement is incorrect if electrolysis of $C H_{3}$ COONa (aq.) is made using Pt electrodes?

Ph of solution increases

Molar ratio of gases at anode and cathode is $3 : 1$

$C H_{3} CO O^{-}$ in solution decreases

The molar ratio of gases at anode and cathode is $2 : 1.$

Ph of solution decreases

At anode:

$2 C H_{3} CO O^{-} ⟶ C_{2} H_{6} + 2 C O_{2 (g)} + 2 e^{-}$

At cathode $: 2 H^{+} + 2 e^{-} ⟶ H_{2 (g)}$

$∴ C O_{2} : H_{2} = 2 : 1$

Q. Which of the statement is incorrect if electrolysis of CH3​ COONa (aq.) is made using Pt electrodes?

Ph of solution increases

Molar ratio of gases at anode and cathode is 3:1

CH3​COO− in solution decreases

The molar ratio of gases at anode and cathode is 2:1.