A force vecF = (5 hati+3 hatj+2 hatk)N is applied over a particle which displaces it from its origin to the poin vecr = (2 hati − hatj)m. The work done on the particle in joules is

Question

A force vecF = (5 hati+3 hatj+2 hatk)N is applied over a particle which displaces it from its origin to the poin vecr = (2 hati − hatj)m. The work done on the particle in joules is (A) −7 (B) +7 (C) +10 (D) +13

Tardigrade Admin · Accepted Answer

Work done, W = vecF⋅ vecs Here vecs = vecrf - vecri = (2 hati- hatj) W = (5 hati+3 hatj+2 hatk) (2 hati- hatj) = 10-3 = 7 J.

Q. A force $F = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) N$ is applied over a particle which displaces it from its origin to the poin $r = (2 \hat{i} - \hat{j}) m .$ The work done on the particle in joules is

−7

+7

+10

+13

Work done, $W = F \cdot s$
Here $s = r_{f} - r_{i} = (2 \hat{i} - \hat{j})$
$W = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) (2 \hat{i} - \hat{j}) = 10 - 3 = 7 J .$

Q. A force F=(5i^+3j^​+2k^)N is applied over a particle which displaces it from its origin to the poin r=(2i^−j^​)m. The work done on the particle in joules is

−7

+7

+10

+13

Work done, W=F⋅s Here s=rf​​−ri​​=(2i^−j^​) W=(5i^+3j^​+2k^)(2i^−j^​)=10−3=7J.

Q. A force $F = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) N$ is applied over a particle which displaces it from its origin to the poin $r = (2 \hat{i} - \hat{j}) m .$ The work done on the particle in joules is

Work done, $W = F \cdot s$
Here $s = r_{f} - r_{i} = (2 \hat{i} - \hat{j})$
$W = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) (2 \hat{i} - \hat{j}) = 10 - 3 = 7 J .$