Q.
A force of 6N acts on a body at rest and of mass 1kg. During this time, the body attains a velocity of 30m/s. The time for which the force acts on the body is
Force (F)=6N; Initial velocity (u)=0;
Mass (m)=1kg and final velocity (v)=30m/s.
Therefore acceleration (a)=mF=16=6m/s2
and final velocity (v)=30=u+at=0+6×t
or t=5 seconds.