A force F =(5+3 y2) acts on a particle in the y-direction, where F is in newton and y is in meter. The work done by the force during a displacement from y=2 m to y=5 m is -J.

Question

A force F =(5+3 y2) acts on a particle in the y-direction, where F is in newton and y is in meter. The work done by the force during a displacement from y=2 m to y=5 m is -J. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

F =5+3 y 2 W=∫ limits25(5+3 y2) d y =[5 y+(3 y3/3)]25 =132 J

Q. A force $F = (5 + 3 y^{2})$ acts on a particle in the $y$ -direction, where $F$ is in newton and $y$ is in meter. The work done by the force during a displacement from $y = 2 m$ to $y = 5 m$ is ___- $J$ .

$F = 5 + 3 y^{2}$
$W = 2 \int 5 (5 + 3 y^{2}) d y$
$= [5 y + \frac{3 y ^{3}}{3}]_{2}^{5}$
$= 132 J$

Q. A force F=(5+3y2) acts on a particle in the y-direction, where F is in newton and y is in meter. The work done by the force during a displacement from y=2m to y=5m is ___-J.

F=5+3y2 W=2∫5​(5+3y2)dy =[5y+33y3​]25​ =132J

Q. A force $F = (5 + 3 y^{2})$ acts on a particle in the $y$ -direction, where $F$ is in newton and $y$ is in meter. The work done by the force during a displacement from $y = 2 m$ to $y = 5 m$ is ___- $J$ .

$F = 5 + 3 y^{2}$
$W = 2 \int 5 (5 + 3 y^{2}) d y$
$= [5 y + \frac{3 y ^{3}}{3}]_{2}^{5}$
$= 132 J$