Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A force F = 3x2 + 2x + 1 acts on a body in the x -direction. The work done by this force during a displacement from x = -1 to +1 is
Q. A force
F
=
3
x
2
+
2
x
+
1
acts on a body in the
x
-direction. The work done by this force during a displacement from
x
=
−
1
to
+
1
is
3447
208
J & K CET
J & K CET 2019
Report Error
A
2
units
B
4
units
C
6
units
D
8
units
Solution:
F
=
3
x
2
+
2
x
+
1
W
=
−
1
∫
1
F
d
x
=
−
1
∫
1
(
3
x
2
+
2
x
+
1
)
d
x
=
[
x
3
+
x
2
+
x
]
−
1
1
⇒
3
+
1
4
units