A flux of 10- 3 Wb passes through a strip having an area A=0.02 m2 . The plane of the strip is at an angle of 60° to the direction of a uniform field B . The value of B is

Question

A flux of 10- 3 Wb passes through a strip having an area A=0.02 m2 . The plane of the strip is at an angle of 60° to the direction of a uniform field B . The value of B is (A) 0.1 T (B) 0.058 T (C) 4.0 textmT (D) none of the above

Tardigrade Admin · Accepted Answer

As the angle between field and plane is

6 0^{o}

, therefore angle between area vector and magnetic field is,

θ = 3 0^{o}

Magnetic flux through the strip is

ϕ = B A cos θ

1 0^{- 3} = B (0.02) cos 3 0^{o}

B = \frac{1 0 ^{- 3}}{( 0.02 ) ( \frac{3}{2} )}

B = 0.058 T

Q. A flux of $1 0^{- 3} Wb$ passes through a strip having an area $A = 0.02 m^{2}$ . The plane of the strip is at an angle of $6 0^{\circ}$ to the direction of a uniform field $B$ . The value of $B$ is

$0.1 T$

$0.058 T$

$4.0 mT$

none of the above

As the angle between field and plane is $6 0^{o}$ , therefore angle between area vector and magnetic field is,
$θ = 3 0^{o}$
Magnetic flux through the strip is
$ϕ = B A cos θ$
$1 0^{- 3} = B (0.02) cos 3 0^{o}$
$B = \frac{1 0 ^{- 3}}{( 0.02 ) ( \frac{3}{2} )}$
$B = 0.058 T$

Q. A flux of 10−3Wb passes through a strip having an area A=0.02m2 . The plane of the strip is at an angle of 60∘ to the direction of a uniform field B . The value of B is

0.1T

0.058T

4.0mT