A flux of 1 mWb passes through a strip having an area A= text0.02 m2 . The plane of the strip is at an angle of 60° to the direction of a uniform field B . The value of B is

Question

A flux of 1 mWb passes through a strip having an area A= text0.02 m2 . The plane of the strip is at an angle of 60° to the direction of a uniform field B . The value of B is (A) 0.1 T (B) 0.058 T (C) 4.0 mT (D) none of the above.

Tardigrade Admin · Accepted Answer

We know that, φ=BAcos θ Angle between overset arrow A and overset arrow B is 30° . φ=1× 10- 3 Wb A=0.02m2 ⇒ 10- 3=B× 2× 10- 2× cos 30o ⇒ B=0.058 T

Q. A flux of $1 mWb$ passes through a strip having an area $A = 0.02 m^{2}$ . The plane of the strip is at an angle of $6 0^{\circ}$ to the direction of a uniform field $B$ . The value of $B$ is

$0.1 T$

$0.058 T$

$4.0 m T$

none of the above.

We know that, $ϕ = B A cos θ$
Angle between $A \to$ and $B \to$ is $3 0^{\circ}$ .
$ϕ = 1 \times 1 0^{- 3} Wb$
$A = 0.02 m^{2}$
$\Rightarrow 1 0^{- 3} = B \times 2 \times 1 0^{- 2} \times cos 3 0^{o}$
$\Rightarrow B = 0.058 T$

Q. A flux of 1mWb passes through a strip having an area A=0.02m2 . The plane of the strip is at an angle of 60∘ to the direction of a uniform field B . The value of B is

0.1T

0.058T

4.0mT