A flow of 107 electrons per second in a conducting wire constitutes a current of

Question

A flow of 107 electrons per second in a conducting wire constitutes a current of (A) 1.6 × 10-12 A (B) 1.6 × 1026 A (C) 1.6 × 10-26 A (D) 1.6 × 1012 A

Tardigrade Admin · Accepted Answer

Flow of electrons, (n/t)=107/sec. Therefore, current (I)=(q/t)=(ne/t)=(n/t) × e =107 × (1.6 × 10-19) = 1.6 × 10-12 A.

Q. A flow of $1 0^{7}$ electrons per second in a conducting wire constitutes a current of

$1.6 \times 1 0^{- 12} A$

$1.6 \times 1 0^{26} A$

$1.6 \times 1 0^{- 26} A$

$1.6 \times 1 0^{12} A$

Flow of electrons, $\frac{n}{t} = 1 0^{7} / sec .$
Therefore, current $(I) = \frac{q}{t} = \frac{n e}{t} = \frac{n}{t} \times e$
$= 1 0^{7} \times (1.6 \times 1 0^{- 19}) = 1.6 \times 1 0^{- 12} A .$

Q. A flow of 107 electrons per second in a conducting wire constitutes a current of

1.6×10−12A

1.6×1026A

1.6×10−26A

1.6×1012A