A flask contains a monoatomic and a diatomic gas in the ratio of 4: 1 by mass at a temperature of 300 K. The ratio of average kinetic energy per molecule of the two gases is

Question

A flask contains a monoatomic and a diatomic gas in the ratio of 4: 1 by mass at a temperature of 300 K. The ratio of average kinetic energy per molecule of the two gases is (A) 1: 1 (B) 2: 1 (C) 4: 1 (D) 1: 4

Tardigrade Admin · Accepted Answer

The average kinetic energy per molecule of any ideal gas is always equal to ((3/2)) kB T. It depends only on the temperature and is independent of the mass and nature of the gas.

Q. A flask contains a monoatomic and a diatomic gas in the ratio of $4 : 1$ by mass at a temperature of $300 K$ . The ratio of average kinetic energy per molecule of the two gases is

$1 : 1$

$2 : 1$

$4 : 1$

$1 : 4$

The average kinetic energy per molecule of any ideal gas is always equal to $(\frac{3}{2}) k_{B} T$ . It depends only on the temperature and is independent of the mass and nature of the gas.

Q. A flask contains a monoatomic and a diatomic gas in the ratio of 4:1 by mass at a temperature of 300K. The ratio of average kinetic energy per molecule of the two gases is

1:1

2:1

4:1

1:4