A fireman wants to slide down a rope. The breaking load for the rope is (3/4)th of the weight of the man. With what acceleration should the fireman slide down? (Acceleration due to gravity is g)

Question

A fireman wants to slide down a rope. The breaking load for the rope is (3/4)th of the weight of the man. With what acceleration should the fireman slide down? (Acceleration due to gravity is g) (A) (g/2) (B) (g/4) (C) (3g/4) (D) Zero

Tardigrade Admin · Accepted Answer

Let the resultant acceleration of fireman be a then R = mg - ma Given R = (3/4) mg ∴ (3/4) mg = mg - ma ⇒ a = (g/4)

Q. A fireman wants to slide down a rope. The breaking load for the rope is $\frac{3}{4}$ th of the weight of the man. With what acceleration should the fireman slide down?
(Acceleration due to gravity is g)

$\frac{g}{2}$

$\frac{g}{4}$

$\frac{3 g}{4}$

Zero

Let the resultant acceleration of fireman be a then
R = mg - ma
Given $R = \frac{3}{4} m g$
$∴ \frac{3}{4} m g = m g - ma \Rightarrow a = \frac{g}{4}$

Q. A fireman wants to slide down a rope. The breaking load for the rope is 43​th of the weight of the man. With what acceleration should the fireman slide down? (Acceleration due to gravity is g)

2g​

4g​

43g​