Question

A fireman wants to slide down a rope. The breaking load for the rope is $\frac{3}{4}$th of the weight of the man. With what acceleration should the fireman slide down?
(Acceleration due to gravity is g)

• A. $\frac{g}{2}$
• B. $\frac{g}{4}$
• C. $\frac{3g}{4}$
• D. Zero

Answer 1

Answer: (B)

Let the resultant acceleration of fireman be a then
$ \, \, \, \, \, \, \, \, \, \, $ R = mg - ma
Given $\, \, \, \, \, \, \, \, \, \, \, \, \, R = \frac{3}{4} mg$
$\therefore \, \, \, \, \, \, \, \, \, \frac{3}{4} mg = mg - ma \Rightarrow a = \frac{g}{4}$