A fireman of mass 60 kg slides down a pole He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5 with what acceleration with the fireman slide down? (g=10 m / s 2)

Question

A fireman of mass 60 kg slides down a pole He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5 with what acceleration with the fireman slide down? (g=10 m / s 2) (A) 1 m / s 2 (B) 2.5 m / s 2 (C) 10 m / s 2 (D) 5 m / s 2

Tardigrade Admin · Accepted Answer

Net downward acceleration <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5a0c42f35557afe15251ee6d7cb8f04b-.png" /> =( text Weight - Frictional force / text Mass ) =(m g-μ R/m) =(60 × 10-0.5 × 600/60) =(300/60)=5 m / s 2

Q. A fireman of mass $60 k g$ slides down a pole He is pressing the pole with a force of $600 N$ . The coefficient of friction between the hands and the pole is $0.5$ with what acceleration with the fireman slide down? $(g = 10 m / s^{2})$

$1 m / s^{2}$

$2.5 m / s^{2}$

$10 m / s^{2}$

$5 m / s^{2}$

Net downward acceleration

$= \frac{Weight - Frictional force}{Mass}$
$= \frac{m g - μ R}{m}$
$= \frac{60 \times 10 - 0.5 \times 600}{60}$
$= \frac{300}{60} = 5 m / s^{2}$

Q. A fireman of mass 60kg slides down a pole He is pressing the pole with a force of 600N. The coefficient of friction between the hands and the pole is 0.5 with what acceleration with the fireman slide down? (g=10m/s2)

1m/s2

2.5m/s2

10m/s2

5m/s2