A faulty thermometer reads 5° C in melting ice and 95° C in stream. The correct temperature on absolute scale will be K when the faulty thermometer reads 41° C.

Question

A faulty thermometer reads 5° C in melting ice and 95° C in stream. The correct temperature on absolute scale will be K when the faulty thermometer reads 41° C. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(41°-5°/95°-5°)=( C -0°/100°-0°) ⇒ C =(36/90) × 100=40° C =313 K

Q. A faulty thermometer reads $5^{\circ} C$ in melting ice and $9 5^{\circ} C$ in stream. The correct temperature on absolute scale will be_______ $K$ when the faulty thermometer reads $4 1^{\circ} C$ .

$\frac{4 1 ^{\circ} - 5 ^{\circ}}{9 5 ^{\circ} - 5 ^{\circ}} = \frac{C - 0 ^{\circ}}{10 0 ^{\circ} - 0 ^{\circ}}$
$\Rightarrow C = \frac{36}{90} \times 100 = 4 0^{\circ} C = 313 K$

Q. A faulty thermometer reads 5∘C in melting ice and 95∘C in stream. The correct temperature on absolute scale will be_______ K when the faulty thermometer reads 41∘C.

95∘−5∘41∘−5∘​=100∘−0∘C−0∘​ ⇒C=9036​×100=40∘C=313K

Q. A faulty thermometer reads $5^{\circ} C$ in melting ice and $9 5^{\circ} C$ in stream. The correct temperature on absolute scale will be_______ $K$ when the faulty thermometer reads $4 1^{\circ} C$ .

$\frac{4 1 ^{\circ} - 5 ^{\circ}}{9 5 ^{\circ} - 5 ^{\circ}} = \frac{C - 0 ^{\circ}}{10 0 ^{\circ} - 0 ^{\circ}}$
$\Rightarrow C = \frac{36}{90} \times 100 = 4 0^{\circ} C = 313 K$