A engine develops 20 kW of power. How much time will it take to lift a mass of 200 kg to a height of 40 m? (g = 10 m/s2)

Question

A engine develops 20 kW of power. How much time will it take to lift a mass of 200 kg to a height of 40 m? (g = 10 m/s2) (A) 4 s (B) 5 s (C) 8 s (D) 10 s

Tardigrade Admin · Accepted Answer

Power P=(mgh/t) (20×103W)=((200 kg)(10 m s2)(40 m)/t) or t=((200 kg)(10 m s2)(40 m)/(20×103w)) t=4 s

Q. A engine develops $20 kW$ of power. How much time will it take to lift a mass of $200 k g$ to a height of $40 m$ ? $(g = 10 m / s^{2})$

$4 s$

$5 s$

$8 s$

$10 s$

Power $P = \frac{m g h}{t}$
$(20 \times 1 0^{3} W) = \frac{( 200 k g ) ( 10 m s ^{2} ) ( 40 m )}{t}$
or $t = \frac{( 200 k g ) ( 10 m s ^{2} ) ( 40 m )}{( 20 \times 1 0 ^{3} w )}$
$t = 4 s$

Q. A engine develops 20kW of power. How much time will it take to lift a mass of 200kg to a height of 40m? (g=10m/s2)

4s

5s

8s

10s