A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after

Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after (A) 21 s (B) 29 s (C) 31 s (D) 37 s

Tardigrade Admin · Accepted Answer

He moves 5 steps forward and 3 steps backward in 8 sec after that he is 2 m away from an initial position x=5-3=2 m in 8 sec after 24 sec he will 6 m away from an initial position He moves further 5 m forward then he falls in a pit which is 11 m away from the initial position. total time T =24+5=29 sec

Q. A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after

21 s

29 s

31 s

37 s

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position x=5−3=2m in 8sec after 24sec he will 6m away from an initial position He moves further 5m forward then he falls in a pit which is 11m away from the initial position. total time T=24+5=29sec