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  4. A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after

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Q. A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after

JIPMERJIPMER 2014Motion in a Straight Line

Solution:

He moves 5 steps forward and 3 steps backward in $8 sec$ after that he is $2 m$ away from an initial position $x=5-3=2 m$ in $8 sec$ after $24 sec$ he will $6 m$ away from an initial position He moves further $5 m$ forward then he falls in a pit which is $11 m$ away from the initial position. total time $T =24+5=29 sec$