A drop of water of radius "r" is falling through the air of coefficient of viscosity 'η' with a constant velocity o f 'v'. The resultant force on the drop is

Question

A drop of water of radius "r" is falling through the air of coefficient of viscosity 'η' with a constant velocity o f 'v'. The resultant force on the drop is (A) (1/6πη r v) (B) 6πη r v (C) √6πη r v (D) zero

Tardigrade Admin · Accepted Answer

When a drop is falling at constant velocity, viscous force is balanced by weight, hence resultant force is zero.

Q. A drop of water of radius "r" is falling through the air of coefficient of viscosity $^{'} η^{'}$ with a constant velocity o f 'v'. The resultant force on the drop is

$\frac{1}{6 π ηr v}$

$6 π ηr v$

$6 π ηr v$

zero

When a drop is falling at constant velocity, viscous force is balanced by weight, hence resultant force is zero.

Q. A drop of water of radius "r" is falling through the air of coefficient of viscosity ′η′ with a constant velocity o f 'v'. The resultant force on the drop is

6πηrv1​

6πηrv

6πηrv​

zero

When a drop is falling at constant velocity, viscous force is balanced by weight, hence resultant force is zero.

Q. A drop of water of radius "r" is falling through the air of coefficient of viscosity $^{'} η^{'}$ with a constant velocity o f 'v'. The resultant force on the drop is

$\frac{1}{6 π ηr v}$

$6 π ηr v$

$6 π ηr v$