A drop of water is about 0.05 mL. The density of, water at room temperature is about 1.0 textm textL-1. The number of water molecules present in a drop of water are.

Question

A drop of water is about 0.05 mL. The density of, water at room temperature is about 1.0 textm textL-1. The number of water molecules present in a drop of water are. (A)  1.67× 1021H2O molecules (B)  1.67× 1026H2O molecules (C)  1.806× 1023H2O molecules (D)  1.806× 1021H2O molecules

Tardigrade Admin · Accepted Answer

d=(m/v) or mass of 0.05 mL water =0.05 mL× 1.0 g mL-1 =0.05 g H2O Moles of H2O=(0.05/18)mol H2O =(6.023× 1023× 0.05/18) =1.67× 1021 H2O textmolecules

Q. A drop of water is about 0.05 mL. The density of, water at room temperature is about $1.0 m L^{- 1} .$ The number of water molecules present in a drop of water are.

$1.67 \times 10^{21} H_{2} O$ molecules

$1.67 \times 10^{26} H_{2} O$ molecules

$1.806 \times 10^{23} H_{2} O$ molecules

$1.806 \times 10^{21} H_{2} O$ molecules

$d = \frac{m}{v}$ or mass of 0.05 mL water
$= 0.05 m L \times 1.0 g m L^{- 1}$
$= 0.05 g H_{2} O$
Moles of $H_{2} O = \frac{0.05}{18} m o l H_{2} O$
$= \frac{6.023 \times 10 ^{23} \times 0.05}{18}$
$= 1.67 \times 10^{21} H_{2} O molecules$

Q. A drop of water is about 0.05 mL. The density of, water at room temperature is about 1.0mL−1. The number of water molecules present in a drop of water are.

1.67×1021H2​O molecules

1.67×1026H2​O molecules

1.806×1023H2​O molecules

1.806×1021H2​O molecules