A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is :

Question

A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is : (A) real and at a distance of 40 cm from convergent lens (B) virtual and at a distance of 40 cm from convergent lens (C) real and at a distance of 40 cm from the divergent lens (D) real and at a distance of 6 cm from the convergent lens

Tardigrade Admin · Accepted Answer

For converging lens u = -40 cm which is equal to 2f ∴ Image will be real and at a distance of 40 cm from convergent lens.

Q. A diverging lens with magnitude of focal length $25 c m$ is placed at a distance of $15 c m$ from a converging lens of magnitude of focal length $20 c m$ . A beam of parallel light falls on the diverging lens. The final image formed is :

real and at a distance of 40 cm from convergent lens

virtual and at a distance of 40 cm from convergent lens

real and at a distance of 40 cm from the divergent lens

real and at a distance of 6 cm from the convergent lens

For converging lens
$u = - 40$ cm which is equal to $2 f$
$∴$ Image will be real and at a distance of 40 cm from convergent lens.

Q. A diverging lens with magnitude of focal length 25cm is placed at a distance of 15cm from a converging lens of magnitude of focal length 20cm. A beam of parallel light falls on the diverging lens. The final image formed is :