A disc is pulled by a force F acting at a point above the centre of mass of the disc. The direction of frictional force (fr) acting on disc pushed on a rough surface will be represented by

Question

A disc is pulled by a force F acting at a point above the centre of mass of the disc. The direction of frictional force (fr) acting on disc pushed on a rough surface will be represented by (A)  (B)  (C)  (D) Information is insufficient

Tardigrade Admin · Accepted Answer

As K2 < R x Here K2=(R2/2), x=R Hence friction will act in forward direction.

Q. A disc is pulled by a force $F$ acting at a point above the centre of mass of the disc. The direction of frictional force $(f_{r})$ acting on disc pushed on a rough surface will be represented by

Information is insufficient

As $K^{2} < R x$
Here $K^{2} = \frac{R ^{2}}{2}, x = R$
Hence friction will act in forward direction.

Q. A disc is pulled by a force F acting at a point above the centre of mass of the disc. The direction of frictional force (fr​) acting on disc pushed on a rough surface will be represented by

Information is insufficient

As K2<Rx Here K2=2R2​,x=R Hence friction will act in forward direction.

Q. A disc is pulled by a force $F$ acting at a point above the centre of mass of the disc. The direction of frictional force $(f_{r})$ acting on disc pushed on a rough surface will be represented by

As $K^{2} < R x$
Here $K^{2} = \frac{R ^{2}}{2}, x = R$
Hence friction will act in forward direction.