Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A disc is pulled by a force $F$ acting at a point above the centre of mass of the disc. The direction of frictional force $\left(f_{r}\right)$ acting on disc pushed on a rough surface will be represented by

System of Particles and Rotational Motion

Solution:

As $K^{2} < R x$
Here $K^{2}=\frac{R^{2}}{2}, x=R$
Hence friction will act in forward direction.