A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lowermost point of the disc.

Question

A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lowermost point of the disc. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vkd2drxegsyulftl.jpg" /> (A) Velocity is v , acceleration is zero (B) Velocity is zero, acceleration is zero (C) Velocty is v , acceleration is (v2/R) (D) Velocity is zero, acceleration is nonzero

Tardigrade Admin · Accepted Answer

From figure <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-vkd2drxegsyuay4z.jpg" /> Vn e t(f o r l o w e s t p o i n t)=v-Rω =v-v=0 and Acceleration=(v2/R)+ O=(v2/R) (Since linear speed is constant) Hence (D)

Q. A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lowermost point of the disc.

Velocity is $v$ , acceleration is zero

Velocity is zero, acceleration is zero

Velocty is $v$ , acceleration is $\frac{v ^{2}}{R}$

Velocity is zero, acceleration is nonzero

From figure

$V_{n e t} (f or l o w es t p o in t) = v - R ω = v - v = 0$
and $A cce l er a t i o n = \frac{v ^{2}}{R} + O = \frac{v ^{2}}{R}$
(Since linear speed is constant)
Hence (D)

Q. A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lowermost point of the disc.

Velocity is v , acceleration is zero

Velocity is zero, acceleration is zero

Velocty is v , acceleration is Rv2​

Velocity is zero, acceleration is nonzero

From figure Vnet​(forlowestpoint)=v−Rω=v−v=0 and Acceleration=Rv2​+O=Rv2​ (Since linear speed is constant) Hence (D)

Velocity is $v$ , acceleration is zero

Velocty is $v$ , acceleration is $\frac{v ^{2}}{R}$

From figure

$V_{n e t} (f or l o w es t p o in t) = v - R ω = v - v = 0$
and $A cce l er a t i o n = \frac{v ^{2}}{R} + O = \frac{v ^{2}}{R}$
(Since linear speed is constant)
Hence (D)