A dipole moment ‘P’ and moment of inertia I is placed in a uniform electric field vecE. If it is displaced slightly from its stable equilibrium position, the period of oscillation of dipole is

Question

A dipole moment ‘P’ and moment of inertia I is placed in a uniform electric field vecE. If it is displaced slightly from its stable equilibrium position, the period of oscillation of dipole is (A) √(PE/I) (B) 2π√(I/PE) (C)  (1/2π) √(PE/I) (D)  π √(I/PE)

Tardigrade Admin · Accepted Answer

Dipole moment = p electric field = E centroid axis = I Explanation When displaced at an angle θ from its mean position the magnitude of restoring torque is T = - p sin θ For small angular displacement sin θ ≈ θ beginarrayl T =- pE θ α=( T / I )=-(( PE / I )) θ =- w 2 θ w2=(P E/I) T =2 π √( I / PE ) endarray (P.E = moment in electric field)

Q. A dipole moment ‘ $P$ ’ and moment of inertia $I$ is placed in a uniform electric field $E$ . If it is displaced slightly from its stable equilibrium position, the period of oscillation of dipole is

$\frac{PE}{I}$

$2 π \frac{I}{PE}$

$\frac{1}{2 π} \frac{PE}{I}$

$π \frac{I}{PE}$

Q. A dipole moment ‘P’ and moment of inertia I is placed in a uniform electric field E. If it is displaced slightly from its stable equilibrium position, the period of oscillation of dipole is

IPE​​

2πPEI​​

2π1​IPE​​

πPEI​​

Q. A dipole moment ‘ $P$ ’ and moment of inertia $I$ is placed in a uniform electric field $E$ . If it is displaced slightly from its stable equilibrium position, the period of oscillation of dipole is

$\frac{PE}{I}$

$2 π \frac{I}{PE}$

$\frac{1}{2 π} \frac{PE}{I}$

$π \frac{I}{PE}$