A diode having potential difference 0.5 V across its junction which does not depend on current, is connected in series with resistance of 20 Ω across source. If 0.1 A passes through resistance, then what is the voltage of the source?

Question

A diode having potential difference 0.5 V across its junction which does not depend on current, is connected in series with resistance of 20 Ω across source. If 0.1 A passes through resistance, then what is the voltage of the source? (A) 1.5 V (B) 2.0 V (C) 2.5 V (D) 5 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/24addfbb6513f6efe26ace6246fb6a23-.png" /> V'=V+IR =0.5+0.1 × 20 =2.5 V

Q. A diode having potential difference $0.5 V$ across its junction which does not depend on current, is connected in series with resistance of $20 Ω$ across source. If $0.1 A$ passes through resistance, then what is the voltage of the source?

1.5 V

2.0 V

2.5 V

5 V

$V^{'} = V + I R$
$= 0.5 + 0.1 \times 20$
$= 2.5 V$

Q. A diode having potential difference 0.5V across its junction which does not depend on current, is connected in series with resistance of 20Ω across source. If 0.1A passes through resistance, then what is the voltage of the source?

1.5 V

2.0 V

2.5 V

5 V

V′=V+IR =0.5+0.1×20 =2.5V

Q. A diode having potential difference $0.5 V$ across its junction which does not depend on current, is connected in series with resistance of $20 Ω$ across source. If $0.1 A$ passes through resistance, then what is the voltage of the source?

$V^{'} = V + I R$
$= 0.5 + 0.1 \times 20$
$= 2.5 V$