A dielectric introduced between the plates of a parallel plate condenser

Question

A dielectric introduced between the plates of a parallel plate condenser (A) decreases the electric field between the plates (B) decreases the capacity of the condenser (C) increases the charge stored in the condenser (D) increases the capacity of the condenser

Tardigrade Admin · Accepted Answer

If a dielectric medium of dielectric constant K is filled completely between the plates then capacitance increases by K times C prime=(K ε0 A/d) ⇒ C prime =K C

Q. A dielectric introduced between the plates of a parallel plate condenser

decreases the electric field between the plates

decreases the capacity of the condenser

increases the charge stored in the condenser

increases the capacity of the condenser

If a dielectric medium of dielectric constant $K$ is filled completely between the plates then capacitance increases by $K$ times
$C^{'} = \frac{K ε _{0} A}{d}$
$\Rightarrow C^{'} = K C$

Q. A dielectric introduced between the plates of a parallel plate condenser

decreases the electric field between the plates

decreases the capacity of the condenser

increases the charge stored in the condenser

increases the capacity of the condenser

If a dielectric medium of dielectric constant K is filled completely between the plates then capacitance increases by K times C′=dKε0​A​ ⇒C′=KC

If a dielectric medium of dielectric constant $K$ is filled completely between the plates then capacitance increases by $K$ times
$C^{'} = \frac{K ε _{0} A}{d}$
$\Rightarrow C^{'} = K C$