A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is

Question

A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is (A) 2, 2-dlibromobutane (B) 1, 1-dibromopropane (C) 1, 4-dibromobutane (D) 1, 2-dibromoethane

Tardigrade Admin · Accepted Answer

ω-dihalides when reacts with sodium metal, gives cyclic hydrocarbons. This is an example of intramolecular Wurtz reaction. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a8a3f13796b4a8a7a40c73d38026ee17-.png" />

Q. A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is________

$2, 2$ -dlibromobutane

$1, 1$ -dibromopropane

$1, 4$ -dibromobutane

$1, 2$ -dibromoethane

$ω$ -dihalides when reacts with sodium metal, gives cyclic hydrocarbons. This is an example of intramolecular Wurtz reaction.

Q. A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is________

2,2-dlibromobutane

1,1-dibromopropane

1,4-dibromobutane

1,2-dibromoethane

ω-dihalides when reacts with sodium metal, gives cyclic hydrocarbons. This is an example of intramolecular Wurtz reaction.

$2, 2$ -dlibromobutane

$1, 1$ -dibromopropane

$1, 4$ -dibromobutane

$1, 2$ -dibromoethane

$ω$ -dihalides when reacts with sodium metal, gives cyclic hydrocarbons. This is an example of intramolecular Wurtz reaction.